When testing for current in a cable with six color-coded wires, the author used a meter to test five wires at a time. How many different tests are required for every possible pairing of five wires? The number of tests required is nothing.

THERE ARE 6 POSSIBLE PAIRING.

Explanation:

There 6 wires and all the possible combinations want to be tested, of 5 of these at a time.

order, or arrangement of the wires within each set of 5 is not important.

By using the combination formula.

c(n,x) = n! / (x! * (n-x)!)

n = 6

x = 5

formula becomes c(6,5) =6!/5!*(6-5)!

= 6! / (5! * 1!)

=6!/5!

=720/120

=6

result is c(6,5) = 6 different test would be required to get all possible combinations of 5 wires each, where order within each set of 5 is not important.

c(6,5) = 8! / (3! * 5!) = 6 possible sets of 5 wires where order within each set of 5 is not important.

because if the tool that you are using is not balanced it there would be false mass.