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Physics, 12.03.2020 02:25 lizzy2951

A proton travels through a region of uniform magnetic field at an angle \thetaθ relative to the magnetic field. The magnitude of the magnetic field in this region is 1.17 T, and the proton's velocity is 500,000 m/s when it experiences an acceleration whose magnitude is 1.50 \times 10^{13}~\frac{m}{s^2}1.50×10 13 s 2 m . Calculate the angle \thetaθ

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