You have constructed a raft that is 2.00 m long, 2.00 m wide, and 0.100 m thick. Part A If the mass of the raft is 20.0 kg and your mass is 55.0 kg, how many 65.0 kg friends can cross a river with you during one trip

5

Explanation:

Volume of raft,

Density of raft,

Total weight= Buoyant force

Assuming n number of friends weighing 65 Kg then

(20+55+65n)g= Buoyant force

Buoyant force will be given by multiplying density of water by volume by acceleration due to gravity

g is on both sides so they cancel

75+65n=400

65n=400-75=325

Therefore, 5 friends each weighing maximum of 65 Kg can go with you on one trip

show the diagram then i will answer

a charge 3q is at the origin, and a charge −2q is on the positive x axis at x=a. part a where on the x-axis would you place a third charge so it would experience no net electric force? enter an expression for the exact answer, which will involve a square-root sign. (do not enter an approximate decimal answer.)