A heat engine operates between 35 C and 330 C. If this engine extracts a total energy of 800 MJ from fuel, then how many MJ of energy could be used as useful mechanical energy? Remember that e = 1 - T(low)/T(high), where T is in Kelvin (= Celsius + 273).

Machine used 392 MJ energy as mechanical energy.

Explanation:

Efficiency(e) is defined as the ratio of the work done by the machine to the energy provided to the machine.

            .....(1)

The efficiency of the machine is also given by the relation :

                .....(2)

Here T(low) and T(high) denotes the temperature in kelvin.

According to the problem, T(low) = 35⁰ C = 35 + 273 = 308 K

                                            T(high) = 330⁰ C = 330 +273 = 603 K

Substitute the values of T(low) and T(high) in the equation (2).

e = 0.49

According to the problem, Energy Given = 800 MJ

Substitute the value of efficiency(e) and Energy Given in the equation (1).

Energy used = 0.49 x 800 MJ = 392 MJ

what was the acceleration of the 2 kg cart?

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what was the acceleration of the 4 kg cart?

⇒ 8.1 cm/s2

what was the acceleration of the 6 kg cart?

⇒ 5.3 cm/s2