Aball is thrown vertically upward from a height of 6 feet with an initial velocity of 41 feet per second. how high will the ball go? (round your answer to two decimal places.)

Given: Height h = 6 ft  or the vertical component "y" this become the initial height, therefore if you want to know the total height of the stone with respect to the ground. you can just add up the two value below.

           Initial Velocity Vi = 41 ft/s     g = -32.2 ft/s²  acting downward

Require: Height h = ?       

Formula: y = Vf² - Vi²/2g

               y = 0 - (41 ft/s)²/2(-32.2 ft/s²)

               y = -1,681 ft²/s²/(-64.4 ft/s²)

               y =  26.10 ft

Answer choices? if there is any

I'd go for the one that says that knees are fulcrums, lower legs are levers and the ankles hold loads.hope it ,happy homework/ study/ exam!