Two blocks are suspended from opposite ends of a light rope that passes over a light, frictionless pulley. One block has mass m1 and the other has mass m2, where m2>m1.The two blocks are released from rest, and the block with mass m2 moves downward 6.00 m in 2.00 s after being released. While the blocks are moving, the tension in the rope is 18.0 N.

Part A

Calculate m1.

Express your answer with the appropriate units.

Part B

Calculate m2.

Express your answer with the appropriate units.

a)  m₁ = 1.41 kg , b)  m₂ = 2.65 kg

Explanation:

For this exercise we will use Newton's second law

Block 1

             T - W₁ = m₁ a

Block 2

           W₂ - T = m₂ a

We have selected the positive  block 1 rising and block two lowering, as the pulley has no friction does not affect the movement

Let's use kinematics to look for acceleration

         y = v₀ t + ½ a t²

As part of the rest the initial speed is zero

           a = 2 y / t²

           a = 2 6.00 / 2²

           a = 3 m / s²

Let's replace in the equation of block 1

a)   T = m₁ g + m₁ a

     m₁ = T / (g + a)

     m₁ = 18.0 / (9.8 + 3)

     m₁ = 1.41 kg

b) we substitute in the equation of block 2

     W₂ - T = m₂ a

     m₂ g - m₂ a = T

     m₂ = T / (g-a)

     m₂ = 18.0 / (9.8 -3)

    m₂ = 2.65 kg

the force on the thing and the distance the force moves the thing

the answer is c. the lower legs are levers, and the knees are fulcrums. the ankles hold the loads.