Bowling balls are roughly the same size, but come in a variety of weights. given its official radius of roughly 0.110 m, calculate the heaviest bowling ball that will float in a fluid of density 1.100

To solve this problem we will apply the concepts related to the balance of forces. In this case the force caused by the weight and the buoyancy force on the Fluid. Both are forces that start from Newton's second law and can be expressed as

Weight

Here,

m = mass

g = Gravity

Buoyant Force

Here

Density of Fluid

=Volume

g = Gravity

By equilibrium we have that

Replacing,

Now the Weight of the balls would be

Therefore the  heaviest bowling ball that will float in this fluid is 60.0936N

the answer is ampere

the ampere is used to measure electricity. an ampere is a unit of electric current equal. a unit of measure for the flow of current in a circuit. one ampere is the amount of current flow provided when one volt of electrical pressure is applied against one ohm of resistance.