Two identical arrows, one with twice the speed of the other, are fired into a bale of hay. assuming the hay exerts a constant frictional force on the arrows, the faster arrow will penetrate how much farther than the slower arrow? explain

Explanation:

When there is frictional force distance traveled by the arrow is s = (v^2)/(2μ_kg)

v= velocity of the object

μ_k = kinetic friction coefficient

g= acc. due to gravity.

as distance is proportional to square of the speed therefore the faster arrow penetrate a distance 4 times the distance penetrate by slower arrow.

answer is c

explanation:

speed of light in vacuum is 300,000 km/s

speed of light in other mediums is given by the expression v = c/n, where c is the speed of light in vacuum and n is the refractive index of medium.

for the first medium v = 200,000 km/s

  so, refractive index of medium = 300000/200000 = 1.5

    1.5 refractive index is usually for glass. so first medium is glass.

for the second medium v = 250,00 km/s

so, refractive index of medium = 300000/250000 = 1.2

    1.2 refractive index is usually for water. so second medium is water.

for the third medium v = 0 km/s

so, refractive index of medium = 300000/0 = ∞

    ∞ refractive index is usually for opaque mediums. so third medium is opaque medium.