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Physics, 20.12.2019 03:31 murtaghliam1

At the instant when the current in an inductor is increasing at a rate of 6.35×10−2 a/s , the magnitude of the self-induced emf is 1.65×10−2 v . you may want to review (pages 994 - 997) . for related problemsolving tips and strategies, you may want to view a video tutor solution of calculating self-inductance.

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