You throw a ball of mass 1 kg straight up. you observe that it takes 2.2 s to go up and down, returning to your hand. assuming we can neglect air resistance, the time it takes to go up to the top is half the total time, 1.1 s. note that at the top the momentum is momentarily zero, as it changes from heading upward to heading downward.

(a) use the momentum principle to determine the speed that the ball had just after it left your hand.
vinitial = ? ? m/s

(b) use the energy principle to determine the maximum height above your hand reached by the ball.
h = ? ? m

10.791 m/s

5.93505 m

Explanation:

m = Mass of ball

= Final velocity

= Initial velocity

= Final time

= Initial time

g = Acceleration due to gravity = 9.81 m/s²

From the momentum principle we have

Force

So,

The speed that the ball had just after it left the hand is 10.791 m/s

As the energy of the system is conserved

The maximum height above your hand reached by the ball is 5.93505 m

  1.the balanced   chemical equation is as below

cu +   2 ag(no)₃ → cu(no₃)₂   +2 ag

2.the   much silver   produced   is   50.9 g

step 1: find the   moles of cu

moles =   mass÷   molar mass

  from periodic table the molar mass of cu = 63.5 g/mol

moles is therefore = 15.00 g÷ 63.5 g/mol = 0.236   moles

step 2: use the mole ratio to determine the   moles of ag

from equation above   cu: ag   is 1: 2

therefore the moles of ag   =0.236   moles   x 2/1 =0.472   moles

step 3: find the mass   of ag

mass = moles x molar mass

from periodic table   the molar mass of ag =107.87 g/mol

mass   = 0.472   moles x 107.87 g/mol = 50.9 g

3.   the   much   silver   collected worth is   1.797 oz

  convert   50.9 g   to oz

that is   1 gram = 0.0353 oz

          50.9 grams =?   oz

by cross multiplication

={(50.9 grams x 0.0353 oz) / 1   gram}   =1.797 oz