Find the equation for the line that passes through (1,-10) that has slope - 9/5

y=-9/5x-41/5

Step-by-step explanation:

A(1,-10) x1=1,y1 =-10

k=-9/5

y-y1=k(x-x1)

y-(-10)=-9/5(x-1)

y+10=-9/5x+9/5

y=-9/5x+9/5-10

y=-9/5x+9/5-50/5

y=-9/5x-41/5

see explanation

step-by-step explanation:

since the sequence is geometric there is a common ratio r between consecutive terms, that is

r = 4 ÷ - 2 = - 2

r = - 8 ÷ 4 = - 2

r = 16 ÷ 8 = - 2

the next term - 13 must be incorrect as it should be - 32 for the sequence to be geometric.

the first 4 terms are therefore geometric with common ratio r = - 2

need more info

step-by-step explanation:

what do you mean by "representation"? graph? table? etc.