Tarzan swings on a 31.0-m-long vine initially inclined at an angle of 42.0° with the vertical. what is his speed at the bottom of the swing if he pushes off with a speed of 6.00 m/s? (pick the answer closest to the true value.)a. 13.9 m/sb. 12.5 m/sc. 8.4 m/sd. 6.9 m/se. 11.0 m/s

Speed of Tarzan at the bottom of the swing is 12.5 m/s.

Explanation:

Given that,

Length of the vine, L = 31 m

The swing is inclined at an angle of 42 degrees with the vertical. We need to find the speed at the bottom of the swing if he pushes off with a speed of 6.00 m/s. using the conservation of mechanical energy as :

h is the height of the height.

v = 12.492 m/s

or

v = 12.5 m/s

So, his speed at the bottom of the swing if he pushes off with a speed of 6.00 m/s is 12.5 m/s. Hence, this is the required solution.