Assume x and y are both differentiable functions of t.

First Substitute x=-1 into the equation 4 + 3 = 28, and you get y=2.

Take the derivative of the equation 4 + 3 = 28, using implicit differentiation:

8x + 9 = 0

Rearrange this in terms of :



Keep in mind that is equal to

Substitute and you will get the following:



Put in the values for x, y, and and solve:

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