A1150 kg car is on a 8.70 hill. what is the normal force on the car?

11,140.33 N

Explanation:

In this case;

Mass = 1150 kg

β = 8.70°

But, g = 9.8 m/s²

Therefore;

Normal force = 1150 kg × 9.8 m/s² × cos 8.70°

                     = 11,140.33 N

Thus, the normal force on the car is 11,140.33 N

1 - wave length

2 - amplitude

3 - crest

4 - trough

explanation:

duh.

it is the second option.