The figure shows four smaller squares in the corners of a large square. the smaller squares have sides of length 1cm, 2cm, 3cm and 4cm in anticlockwise order and the sides of the large square have length of 11cm. What is the area of the shaded quadrilateral? (see attachment)

B. 36

Step-by-step explanation:

The shaded quadrilateral has a shape of a trapezium.

Area of a trapezium = (a + b)h

where: a is the side length parallel to the base, b is the base and h is the height.

The height of the figure = 11 - (4 + 1)

                                        = 11 - 5

                                        = 6

The height of the figure is 6 cm.

The length of its base = 11 - (1 + 2)

                                    = 11 - 3

                                    = 8

The length of its base is 8 cm.

The length of the side parallel to base = 11 - (4 + 3)

                                     = 11 - 7

                                     = 4

The parallel side length to base is 4 cm.

Area of quadrilateral = (a + b)h

                                     = (4 + 8)6

                                    = 12 x 3

                                    = 36

Area of quadrilateral = 36

just find the gcf and solve the gcf's until you get each answer i have a really good feeling somethings missing xd (like the dimensions of the fence) *cough *cough *hint *hint

step-by-step explanation:

the value of v.w= -12.

step-by-step explanation:

we are given three vector r,v and w as:

r = < 5, -5, -2> ; v = < 2, -8, -8> ; w = < -2, 6, -5>

we know that r,v and w could also be represented as:

r=5i-5j-2k

v=2i-8j-8k

and w= -2i+6j-5k

where i,j and k are the unit vectors of x,y and z-axis respectively.

also we know that it has the following property:

i.i=1 ; j.j=1; k.k=1

and i.=j.i=i.k=k.i=j.k=k.j=0

i.e. when we multiply two vectors or we find it's dot product we need to only multiply the components of x coordinates with each other; y with each other and z with each other.

hence, v.w= (2i-8j- -2i+6j-5k)

                  = 2×(-2)+(-8)×(6)+(-8)×(-5)

                  = -4-48+40

                  = -12

hence, v.w= -12