The cern particle accelerator is circular with a circumference of 7.0 km.
(a) what is the acceleration of the protons (m = 1.67 × 10−27 kg) that move around the accelerator at 5% of the speed of light? (the speed of light is v = 3.00 × 108 m/s. )
(b) what is the force on the protons?

Explanation:

m = Mass of proton =

v = Speed of proton = 0.5c =

Circumference of the colider is 7 km

Centripetal acceleration is

Force on protons is

graph question answered .. you think better when you are relaxed and happy

false.

explanation:

this statement is false. after falling for 5 seconds, its speed will not be 100 m/s.