Disregarding air resistance, what is the speed of a ball dropped from 12 feet just before it hits the ground? (use 1 ft = 0.30 m, and use g = 9.8 m/s2.)

This is an example of a free-fall problem. This can be solved using the following free-fall equation:

Let: V = velocity; g = acceleration due to gravity (9.8 m/s^2); h = 12 feet

V^2 = 2gh or V = √(2gh)

It is important that we use similar units of measurement, so let us convert the height from feet to meters using the given relationship 1 ft = 0.30m.

12 feet x 0.30m = 3.6m

Subsituting the given values to the formula:

V = √(2gh)

V = √(2 x 9.8 x 3.6)

V = √(70.56)

V = 8.4 m/s | This is the speed of the ball dropped just before it hits the ground

The purpose of a lab is to do your "expirements" the importance of the topic is so you can now what the story is about and the last one is because no one is me with my question ( what is 3 over 4 x - 9 = 27 maybe you can )