Gquestions 1 - 4 compute forces in the members of the 2d truss below. the truss has an overall height of 4 meters and an overall length of 12 meters (there are 8 members along the bottom which each are 1.5 meters long). if the member is in compression, use a negative sign in the answer to indicate compression. work in units of kj for forces but do not enter units. determine the force in member kj. kj =

FKJ = 0    (It does not work).

Explanation:

The truss has an overall height of 4 meters and an overall length of 12 meters (there are 8 members along the bottom which each are 1.5 meters long). If the member is in compression, use a negative sign in the answer to indicate compression. Work in units of kN for forces but do not enter units. Determine the force in member KJ.

Ax = 0    ⇒   Ix = 0

∑ MA = 0   (counterclockwise +)   ⇒   - 10*3 – 6*9 – 6*10.5 + Iy*12 = 0  

⇒  Iy = 12.25 N  (↑)

∑ Fy = 0   (↑)  

Ay – 10 – 6 - 6 + Iy = 0      ⇒    Ay = 10 + 6 + 6 - 12.25      ⇒    Ay = 9.75 N (↑)

∑ MK = 0   (counterclockwise +)   ⇒  - FHI*4 + Iy*3 = 0  

⇒  FHI = (Iy*3) / 4 = (12.25*3) / 4

⇒  FHI = + 9.1875 N  

Node I:  

∑ Fx = 0   (→)  

FRI*Cos (θ) - FHI = 0     ⇒   FRI = FHI / Cos (θ) = 9.1875 / (3/5) = 15.3125 N

⇒   FRI = - 15.3125 N

Now, for the section in the figure 2 shown we have

∑ Fx = 0   (→)

⇒   FKJ + FRI*Cos (θ) - FHI = 0    

⇒    FKJ = FHI - FRI*Cos (θ) = 9.1875 - 15.3125*(3/5)

⇒   FKJ = 0    (It does not work).

protons in

as we probably am aware that our atmosphere or air have various levels, each level has different gasses, and each gas has another porousness. at the point when the light originates from lower porousness to higher penetrability, it alters its course. with the goal that implies that when the light originates from the moon to the earth, it alters it's course a lot more occasions. it essentially implies that the state of the light piece of the moon is changed on the earth.

not copied too! hope this !

joke:

h o h o hope you have a merry christmas!