You and your friend throw balloons filled with water from the roof of a several story apartment house. you simply drop a balloon from rest. a second balloon is thrown downward by your friend 2.2 s later with an initial speed of 43.12 m/s. they hit the ground simultaneously. how high is the apartment house? the acceleration of gravity is 9.8 m/s 2 . neglect air resistance. answer in units of m.

Height = 53.361 m

Explanation:

There are two balloons being thrown down, one with initial speed (u1) = 0 and the other with initial speed (u2) = 43.12

From the given information we make the following summary

= 0m/s

= t

= 43.12m/s

= (t-2.2)s

The distance by the first balloon is

where

a = 9.8m/s2

Inputting the values

The distance traveled by the second balloon

Inputting the values

simplifying

Substituting D of the first balloon into the D of the second balloon and solving

Now we know the value of t. We input this into the equation of the first balloon the to get height of the apartment

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