Suppose that at room temperature, a certain aluminum bar is 1. m long. the bar gets longer when its temperature is raised. the length l of the bar obeys the following relation: l=1.+2.4×10−5t, where t is the number of degrees celsius above room temperature. what is the change of the bar's length if the temperature is raised to 13.0 ∘c above room temperature?

ΔL =0. 000312  m

Explanation:

Given that

At  room temperature ( T = 25 ∘C)  ,L= 1 m

So the length at  13.0 ∘C above room temperature

L=1.000312 m

So the change in length

ΔL = 1.000312 - 1.0000 m

ΔL =0. 000312  m

see the picture for the vector

the magnitude of the vector by pythagorean theorem

r = √( (-10)^2 + (3)^2 ) = √109

magnitude = √109 units

the direction angle between vector and x-axis is

tan^(-1)(3/10) = 16.699

so the direction is approximately 16.7 degrees north of west