13500kg/h of carbon tetrachloride is to be cooled in a parallel flow condenser from 850c to 700c. 19000kg/h of cooling water is available at 200c. wall resistance is negligible and hi on the water side including fouling factors is 2000 w/m2-0c. additional information: ccl4—boiling point 76.80c; latent heat, 46.4 cal/g; heat capacity (gas), 0.24 cal/g-0c; heat transfer coefficient, 60 w/m2-0c (gas), 800 w/m2-0c (liquid), and 2400 w/m2-0c (condensing vapor); no fouling on the outside. determine the fractional area for the three sections (desuperheater, condenser and sub-cooler) and compare them with the respective load fractions.

The answer is b.the gaseous state is electrically positive, while the plasma state is electrically negative. 

Answer: a charge of -1.0  × 10⁻⁴ c must be placed  at x = 26 m.the sign of the charge will be the same sign as the  -4.0  µc charge.======electricstatic force between two point charges  is given by    where k is coulomb's constant,  8.99×10⁹  n·m²/c², q₁ and q₂ are the point charges, and r is the distance between the two point charges.assign positive to q₁let q₁ =  6.0 µc, q₂ = -4.0  µc, q₀ represent the charge at the origin, and q₃ represent this new charge to place.the charge at the origin q₀ would experience the following force f₀₁ from q₁, with r = 6.0 m (note that 1  µc = 10⁻⁶ c)    the force from q₂    the force from q₃    the net force on the origin charge, q₀, has to be zero for no electrostatic forcehaving an equation where k and q₀ can be divided out of the equation will allow us to solve for q₃    isolating:     a charge of -1.0  × 10⁻⁴ c must be placed  at x = 26 m.the sign of the charge will be the same as the  -4.0  µc charge