What is the total charge of the radon nucleus? (the neutral radon atom has 86 electrons.) tries 0/20 what is the magnitude of its electric field at a distance of 1.96×10-10 m from the nucleus? tries 0/20 what is the magnitude of the force on an electron at that distance? tries 0/20 what would the magnitude of the force be if the distance of the electron from the nucleus were halved?

Answerthe energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.explanationwe define electric potential as the ratio electric potential energy to the charge,    then the following gives us the potential difference,      the formula  may be on your formula sheet.the change in electric potential energy would be the energy that would needed to move it from point a to point b. solving for that, we get    using q = 8.00  × 10⁻¹⁹ c and  δv = 2.00 v, we get    the energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.

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