Initially, a particle is moving at 5.24 m/s at an angle of 35.2° above the horizontal. four seconds later, its velocity is 6.25 m/s at an angle of 57.5° below the horizontal. what was the particle's average acceleration during these 4.00 seconds in the x-direction (enter first) and the y-direction?

- 0.23

0.56

Explanation:

= initial velocity of the particle = =

= final velocity of the particle = =

t = time interval = 4.00 sec

= average acceleration = ?

Using the kinematics equation

= + t

= + (4)

= 4

=

hence

Average acceleration along x-direction = - 0.23

Average acceleration along y-direction = 0.56

the box does not move because you need to use a force greater than 300 n. you are only using 50 n. it needs to at least be 301 n for the box to move because then it is an unbalanced force and it will move the way that the greater force is pushing it. if you use only 300 n it will be a balanced force and will not move because the force you are exerting on the   box is the same as its force.

hope this !

im sorry if i went too in depth, i am going to include a link to a video on khan academy that will explain this.   hope that you like the video and that it explains more in detail to you.

that is the link.