Atraveling electromagnetic wave in a vacuum has an electric field amplitude of 69.1 v/m . calculate the intensity of this wave. then, determine the amount of energy that flows through area of 0.0247 m^2 over an interval of 13.1 s, assuming that the area is perpendicular to the direction of wave propagation.

The intensity of this wave and energy is 6.3385 N/m² and 2.0509 J.

Explanation:

Given that,

Electric field amplitude E₀= 69.1 V/m

Area A= 0.0247 m²

Time t= 13.1 s

We need to calculate the intensity

Using formula of intensity

Where, c = speed of light

Put the value into the formula

(b). We need to calculate the energy

Using formula of energy

Where, A = area

t = time

S = intensity

Put the value into the formula

Hence, The intensity of this wave and energy is 6.3385 N/m² and 2.0509 J.

hi there!

out of the two, (b) precision would be more reasonable.   however, both a and b could be pretty reasonable.

-awesomerepublic   : )