1.light of wavelength 633 nm passes through a narrow slit and forms a diffraction pattern on a screen 8.0 m away. a distance of 23 mm separates the centers of the first minima on either side of the central bright fringe. what is the distance between the fourth minima on both sides of the central bright fringe?

my answer is c

2.light of wavelength 633 nm from a distant source is incident on a slit with a width of 0.750 mm wide. a diffraction pattern is observed on a screen 3.50 m away. what is the distance between the dark fringes on either side of the central maximum?
my answer is a

(a) 184 mm

The formula for the diffraction from single slit is:

where

y is the distance of the mth-minimum from the central maximum

is the wavelength

D is the distance of the screen from the slit

a is the width of the slit

In this problem, we have:

D = 8.0 m

for m = 1

Solving for a, we find the width of the slit:

Now we can find the distance of the 4th minimum from the central maximum:

So, the distance between the forth minima on both sides of the central maximum is

(b) 5.90 mm

Again, we can use the formula

where in this situation:

D = 3.50 m

Solving for m = 1, we find the distance of the first minimum from the central bright fringe:

And so, the distance between the two minima is

are you like autistic or something?

xd

see the picture for the vector

the magnitude of the vector by pythagorean theorem

r = √( (-10)^2 + (3)^2 ) = √109

magnitude = √109 units

the direction angle between vector and x-axis is

tan^(-1)(3/10) = 16.699

so the direction is approximately 16.7 degrees north of west