The image shows a geometric representation of the function f(x) = x2 – 2x – 6 written in standard form. what is this function written in vertex form? a) f(x) = (x –1)2 – 7 b) f(x) = (x +1)2 – 7 c) f(x) = (x –1)2 – 5 d) f(x) = (x +1)2 – 5it has to be a, b, c, or d someone has asked this question before but whoever answered it just copied and pasted the question that was asked as the answer so the answer has to be one of the above.

The vertex form of the equation of a parabole is (x - h)^2 + k

So you must complete squares to transform x^2 -2x - 6 in its vertex form.

1) convert x^2 - 2x in a square => (x - 1)^2 - 1

2) Add the constant term - 6 => (x - 1)^2 -1 - 6

3) Add similar terms => (x - 1)^2 - 7

You can verify that (x - 1)^2 - 7 is equal to x^2 - 2x - 6:

x^2 - 2x + 1 - 7 = x^2 - 2x - 6. So, do not doubt it, the vertex form is (x - 1)^2  - 7, where the coordinates of the vertex are (1, - 7)

option A (x - 1)^2 - 7