Aracing car reaches a speed of 42 m/s. it then begins a uniform negative acceleration, using its parachute and braking system, and comes to rest 5.5 s later. find the distance that the car travels during braking

As per the question the initial speed of the car [ u] is 42 m/s.

The car applied its brake and comes to rest after 5.5 second.

The final velocity [v] of the car will be zero.

From the equation of kinematics we know that

                                          [ here a stands for acceleration]

Here a is taken negative as it the car is decelerating uniformly.

We are asked to calculate the stopping distance .

From equation of kinematics we know that

                                               [here S is the distance]

                                                             [ans]  

what are the statements? x

d.7.5cm is your answer