Points f, g, and h are collinear such that fg: fh=2/3.if a directed line segment begins at f(-3,2) and ends at h (-3,7), find the coordinates of point g

We consider the x- and y-coordinates separately. Let the coordinates of G be (x, y). Now considering the x-coordinates:
FG/FH = (x - (-3)) / (-3 - (-3)) = 2/3
x + 3 = (2/3)(6)
x = 1
For the y-coordinates:
FG/FH = (y - 2) / (7 - 2) = 2/3
y - 2 = (2/3)(5)
y = 16/3
Therefore the coordinates of G are (1, 16/3).

Gdjehhjjjbb bvggcddfghg bbgg