For the first 30 km, the bicyclist rode with a speed of v km/hour. for the remaining 17 km he rode with a speed which was 2 km/hour greater than his original speed. how much time did the bicyclist spend on the entire trip? let t be the time (in hours), and find t if:

If v = 15 km/h We have:

 d1 = 30 km

 d2 = 17 km

 Since speed = distance/time follows time = distance/speed.

 The total time of the entire trip is is the sum of the time of the first 30 km and the time of the remaining 17 km:

 d1/v + d2/(v + 2) = 30/15 + 17/(15 + 2) = 2 + 1 = 3 hours

 The answer is t=3hours

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