Mark estimates that the distance from his house to his school is 15.5 mi. the actual distance is 14.5 mi. to the nearest tenth of a percent, what is the percent error in mark's estimate?

The percentage error of the estimate is 6.9%

The data values are given as:

Actual = 14.5 miles

Estimate = 15.5 miles

The percentage error in the estimate is then calculated as:

So, we have:

Evaluate

Hence, the percentage error of the estimate is 6.9%

Read more about percentage error at:

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the simplified form is

step-by-step explanation:

we want to simplify the expression,

let us change the middle bar to a normal division sign to obtain,

we multiply the first fraction by the reciprocal of the second fraction to obtain,

we factor to obtain,

we cancel the common factors to get,

we simplify to get,

the correct answer is b

and?

step-by-step explanation: