Evaluate each expression. (25^-3/2)^1/3=

25⁻³ = .000064  .000064 / 2 = .000032.000032¹/³ =.031748021

(1/(25^3×2))^(1/3)25^3 = 25×25^2: (1/(25×25^2×2))^(1/3)  | 2 | 5× | 2 | 51 | 2 | 55 | 0 | 06 | 2 | 5: (1/(25×625×2))^(1/3)25×625 = 15625: (1/(15625×2))^(1/3)15625×2 = 31250: (1/31250)^(1/3)(1/31250)^(1/3) = (1^(1/3))/(31250^(1/3)): (1^(1/3))/(31250^(1/3))31250^(1/3) = (2×5^6)^(1/3) = 5^2 2^(1/3): (1^(1/3))/(5^2 2^(1/3))5^2 = 25: (1^(1/3))/(25 2^(1/3))rationalize the denominator. (1^(1/3))/(25 2^(1/3)) = (1^(1/3))/(25 2^(1/3))×(2^(2/3))/(2^(2/3)) = (1^(1/3)×2^(2/3))/(25×2): (1^(1/3)×2^(2/3))/(25×2)25×2 = 50: answer: (1^(1/3)×2^(2/3))/(50)

Subtract 2 from all the first numbers and add 3 to all the second ones for new coordinates

It would have infinite solutions.