Acertain car traveling at 34.0 mph skids to a stop in 29 meters from the point where the brakes were applied. in approximately what distance would the car have stopped had it been going 105.4 mph?

Using the kinematic equations: (final velocity)^2 = (initial velocity)^2 - 2 * acceleration * distance Assuming the acceleration/deceleration on the car is constant from a constant force on the brakes. Converting from mph to m/s using 0.447 (so 34 mph is 15.2 m/s) (0)^2 = (15.2)^2 - 2 * acceleration * 29 acceleration = 4.0 m/s^2 Had the car been going 105.4 mph (47.1 m/s) (0)^2 = (47.1)^2 - 2 * 4 * distance distance = 277 meters