Aspecial 8 sided die is rolled 20 times with these outcomes: 2, 4, 7, 3, 1, 5, 4, 6, 3, 8, 6, 2, 5, 2, 6, 1, 7, 4, 5, 6, what is the experimental probability of rolling a 2 or a 4? is this number greater than or less than the theoretical probability of rolling a 2 or a 4? explain

Yes, the experimental probability of rolling a 2 or a 4 is greater than theoretical probability of rolling a 2 or a 4.

We are given the outcomes of an experiment as:

2, 4, 7, 3, 1, 5, 4, 6, 3, 8, 6, 2, 5, 2, 6, 1, 7, 4, 5, 6.

Total number of outcomes are:  20

Number of times 2 or 4 comes up is:  6

Hence, the experiment probability of rolling a 2 or a 4 is:

                             6/20=3/10

Also, the theoretical probability of rolling a 2 or a 4 is:

                                2/8=1/4

( Since there are total 8 outcomes possible on rolling a cube and there are two outcomes which are 2 or 4)

Also, we know that:

1/4 < 3/10

This means that the experimental probability is greater than the theoretical probability.

the answer is 844

step-by-step explanation:

it is 844 because if you add 836.50 + 7.5 you will get 844

step-by-step explanation: