Will mark brainliest:

what is the equation of a line that passes through the point (1, 8) and is perpendicular to the line whose equation is y=x/2+3?

The answer to your question is:         y = -2x + 10

Step-by-step explanation:

Data

Point = (1, 8)

Line    y = x/2 + 3

perpendicular

slope = 1/2  but the lines are perpendicular, then slope = -2

Equation

                    ( y - y1) = m ( x - x1)

                     (y - 8) = -2(x  - 1)

                     y - 8 = -2 x + 2

                     y = -2x + 2 + 8

                    y = -2x + 10

a) 0

step-by-step explanation:

i^413 x i^0 = 0 as any number multiplied by a zero is

happy to

pls mark as brainliest.