Seth opens a savings account with $300. The annual interest rate is 6% how much simple interest will Seth earn after 2 years? Use the formula for simple interest: I=pxrxt.

$36

Step-by-step explanation:

The p stands for principal (amount of money that is in the account), r is the rate (the percentage of interest) and t is the time (time can be recorded in any format e.g. years, months, weeks but the most common one is years). First you take the p from the equation and replace it with 300, then you take 6% and then replace the t for 2. 300 multiplied by 6% is 18. this is the interest for one year. 18 times by 2 (the amount of time in the equation) is 36. So after two years Seth will earn $36 and the total amount of money in his account will be $336

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.