Pea aphids, Acyrthosiphon pisum, are small, wingless, sap‑sucking insects that live on plants. They evade predators (such as ladybugs) by dropping off of the plants. A study examined the mechanism of aphid drops. Researchers placed aphids on a leaf positioned at four different heights (in centimeters, cm) above a surface covered with petroleum jelly. When a ladybug was introduced, the aphids dropped, and the petroleum jelly helped capture their landing posture (upright or not). Each aphid performed this experiment only once. Calculate the percentage of aphids that land upright when dropped from the indicated heights. (Enter your answers rounded to one decimal place.)

dropped from 33 cm:

%

dropped from 55 cm:

%

dropped from 10 cm:

%

dropped from 20 cm:

Landing PostureDropping Height
33 cm55 cm1010 cm2020 cm
Upright1919232328283030
Not upright1212883311
Sample Size3131313131313131

$450 i think. hope this ☺

hello!

to begin with, we're given that on earth, a rock weighs 20 pounds, and while on jupiter, that same rock weighs 42 pounds. now, we're trying to find the weight of a rock that weighs 10.5 pounds on earth, on jupiter.

to solve this, first, set up a proportion, cross-multiply, and solve it algebraically.

setting up the proportion is the hardest and the most confusing part of the problem, but it's simple.

if on earth, the rock weighs 20 lbs, and on jupiter it weighs 42 lbs, our first part of our proportion is 20/42 lbs. the second part has to be equal to each other. this means that 10.5 has to be on the numerator of the fraction, and x, the value we're trying to find, has to be on the denominator. remember that the rock weighs 10.5 lbs on earth, and we're trying to find the weight of it on jupiter (which is x).

20/42 = 10.5/x

next, you would cross-multiply.

20x = 42(10.5)

20x = 441

now, solve it algebraically by using division.

x = 22.05 lbs

this can be rounded to 22.1 lbs.

therefore, the weight of the rock on jupiter is 22.1 lbs, the fourth choice.

w< 4

step-by-step explanation: