The length of a rectangle is 1 yd more than twice its width, and the area of the rectangle is 66yd^2 . Find the dimensions of the rectangle. Length:
Width:

Step-by-step explanation:

Based on information from BOTH passages, which draws the MOST logical conclusion?

A) Both authors will resolve growing conflicts with a marriage,

B) The passages are written about distinctly different time periods.

C) The authors use a style largely dependent on flashback narrative,

D) Both passages will continue to address the theme of unrequited love.

width=5.5

Length=12

Step-by-step explanation:

L = 1+2W       [eq2; “length of the rectangle is 1 yd more than twice the width”]

(1+2W)(W)=66      [substitute eq2 for L in eq1]

W + 2W2= 66       [distribute]

2W2+ W – 66 = 0     [put all term on left side]

(2W-11)(W+6) = 0      [factor or use Quadratic Formula]

Substitute for W in either formula:

L = 1 + 2(5.5)

(i don't know if you understand this)

1.0

step-by-step explanation:

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length