Select from the drop-down menus to correctly complete the proof. To prove that 4π is irrational, assume the product is rational and set it equal to ab, where b is not equal to 0: 4π=ab. Isolating π gives π=a4b. The right side of the equation is Choose.(rational or Irrational).. . Because the left side of the equation is Choose.(rational or irrational).. , this is a contradiction. Therefore, the assumption is wrong, and the number 4π is Choose(rational or Irrational)... .

i wish i could u

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i wish i could u

where did you get them? if you picked from the grass, is is probably poisonous.

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guess at question:

a vertical line intersects the graph of g(x,y) = 0 at two points. what conclusion follows about the function f(x) implicitly defined by g(x,f(x)) = 0?

the domain of f(x) cannot include the x coordinate of any such vertical line.

informally, f(x) is not a function, and

g(x,y)=0 cannot be solved for y uniquely.

the relation r = {(x,y) such that g(x,y) = 0} is a function if

for all (a,b) ∊ r and (c,d) ∊ r, a=c implies b=d.

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answer: the resulting cross section is a rectangle. solution: a plane parallel to the base of a triangular prism will intersect a cross section that is the same shape as its bases. so the cross section is a triangle.

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