The factorization of 12a^2b+15ab^2 gives: 1 point
3ab(4a+5b)
3b(4a + 5b)
3a(4a+5b)
3ab(4ab+5)
The factorization of 12x+36 is
1 point
12(x+3)
12(3x)
12(3x+1)
x(12+36x)
On factorising 14pq + 35pqr, we get:
1 point
pq(14+35r)
p(14q+35qr)
7pq(2+5r)
q(14p+35pr)
The factors of x^2 +xy+8x+8y are:
1 point
(x+y) (x+8)
(x+2y) (x+8)
(2x+y) (x+8)
(x+y) (2x+8)
Which of the following are the factors of a^2 + ab +bc + ca
1 point
(b + c) (c + a)
(a + b) (a + c)
a(a + b + c)
(a + b) (b + c).
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answer: b

step-by-step explanation: im sorry bro bro but thats not a eqation the human mind can answer and plus im a devil

the correct answer option is (2x-3)(2x+3).

step-by-step explanation:

we are given the following expression and we are to factorize it:

we are to find such factors that when multiplied they give a result of 36 (9 x 4 = 36) and when added they give a result of 0.

the two such factors of 36 are negative six and postive six.

factorizing the given expression to get:

therefore, the correct factorization of is (2x-3)(2x+3).

answer:  

step-by-step explanation:

odd numbers are only divisible by 1 and itself.

even numbers are divisible by more than 1 and itself.

for example 6 is even because it is divisible by more than 1 and its self. 1 x 6= 6 ; 2 x 3= 6

and 7 is odd because only 7 x 1 equals seveb

b. 18

step-by-step explanation:

so the equation for this is:

ab^2=ac⋅ad

ab being the top length of 6 and ac being the length of 2 and ad being the length of x. let's plug into the equation:

6^2 = 2x

now lets just solve for x:

36 = 2x

18 = x

i hope that !