What is the general equation of a cosine function with an amplitude of 3/2, a period of π and a vertical shift of –½? A. -3 cos (2x + π/5) -1/2
B. -3/5 cos (x + π/2) -1/2
C. -2 cos (2x + π) +1/2
D. -3/2 cos (2x + π/3) -1/2

idk man good luck man

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )

step-by-step explanation:

*calories burned = (weight)(calorie factor)*

calories burned = 180 (0.65)

calories burned = 117

the calories he used up is 117, which is 65% of his weight.  

you have 6 equal triangles, find the area of one of them (b*h/2) and multiply by 6

(8*4: 2)*6 =

32 cm² is your answer