Chemistry, 31.08.2019 02:00 jetskiinbunny31

Which element(s) is/are not balanced in this equation?
pb(no3)2 +2 kcl -> pbcl2 + kno3

Answers: 2

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Answer from: arangoaiden71

Answer : The elements not balanced in this equation are, nitrogen (N), potassium (K) and oxygen (O).

Explanation :

Balanced chemical reaction : It is defined as the number of atoms of individual elements present on reactant side must be equal to the product side.

The given unbalanced chemical reaction is,

$Pb(NO_3)_2+2KCl\rightarrow PbCl_2+KNO_3$

This chemical reaction is an unbalanced reaction because in this reaction, the number of atoms of nitrogen, potassium and oxygen are not balanced while all the atoms are balanced.

In order to balanced the chemical reaction, the coefficient 2 is put before the 'KNO_3' .

Thus, the balanced chemical reaction will be,

$Pb(NO_3)_2+2KCl\rightarrow PbCl_2+2KNO_3$

Hence, elements not balanced in this equation are, nitrogen (N), potassium (K) and oxygen (O).

Answer from: Quest

The answer should be vaporization

Answer from: Quest

remember that hf is only the energy of one photon. not two. not three. one. 1) 5.12 * 10^3 photons find the energy of one photon, then determine how many photons are needed to reach the sensitivity. e = hf = (6.626 * 10^-34 js)(5.95 * 10^19 hz) = 3.94247 * 10^-14 j per photon (2.02 * 10^-10 j) / (3.94247 * 10^-14 j/photon) = 5123.69149 photons round to three sig figs. 2) 5.77 * 10^-17 j energy of pulse = energy per photon * number of photons = hfn = (6.626 * 10^-34 js)(1.66 * 10^13 hz)(5250) = 5.774559 * 10^-17 j round to three sig figs. 3) 4.07 * 10^8 kj/mol 10^12 pm = 1 m c = fλ f = c/λ e = hf = hc/λ = [(6.626 * 10^-34 js)(3.00 * 10^8 m/s) / (2.94 * 10^-12 m)](1 kj/1000 j)(6.02 * 10^23 photons/mol) = 40702571.4 kj/mol round to three sig figs. 4) 9.94 * 10^-1 m e = hc/λ λ = hc / e = (6.626 * 10^-34 js)(3.00 * 10^8 m/s) / (2.00 * 10^-25 j) = 0.9939 m round to three sig figs. 5) 9.06 * 10^3 photons energy of pulse = energy per photon * number of photons number of photons = energy of pulse / energy per photon = energy of pulse / (hf) = (3.87 * 10^-13 j) / [(6.626 * 10^-34 js)(6.45 * 10^16 hz)] = 9055.23695 photons round to three sig figs. 6) 2.78 * 10^-15 j this is problem 1, except in reverse. sensitivity = minumum number of photons * energy per photon = (5930)(6.626 * 10^-34 js)(7.077 * 10^14 hz) = 2.78070758 × 10^-15 j round to three sig figs.

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Which element(s) is/are not balanced in this equation?
pb(no3)2 +2 kcl -> pbcl2 + kno3...

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