Write an equation of a parabola with x-intercepts at (1/4,0) and (-7,0) which passes through the point (0,7).

f(x) = - 4x² - 27x + 7

Step-by-step explanation:

f(x) = a*(x-1/4)(x+7) = a(x² + 27/4 x - 7/4)

pass (0,7):   7 = a (-7/4)

a = -4

f(x) = -4*(x² + 27/4 x - 7/4)

f(x) = -4x² - 27x + 7

hi,

i'm 75% sure the answer is 1,1 to both lines.

have a great day

(0,-3) see attached graph

step-by-step explanation:

a. to solve the system, graph the two equations.

x = y+3 becomes y=x-3 has m=1/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move up 1 unit and 1 unit to the right. plot a point and connect.

y=-4x+3 has m =-4/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move down four units and to the right 1 unit. plot a point and connect.

the solution is the point (x,y) where the two lines intersect. by the graph below it is (0,-3).

b. to solve by substitution, substitute y = -4x-3 into x= y+3

x= (-4x-3) +3

x=-4x

5x=0

x=0

now substitute x = 0 back in to find y.

y= -4(0)-3

y=0-3

y=-3

solution is (0,-3)

c. use elimination by adding the equations together.

x-y=3

4x+y=-3

5x=0

x=0

then substitute into one equation to find y.

y=-4(0)-3

y=-3