2sin^2(2x) + 1 = 3sin(2x) Solve for x with exact answers. The domain is 0 ≤ x ≤ π

x = π/12 and x = π/4.

Step-by-step explanation:

2sin^2(2x) + 1 = 3sin(2x)

2sin^2(2x) - 3sin(2x) + 1 = 0

(2sin(2x) - 1)(sin(2x) - 1) = 0

2sin(2x) - 1 = 0

2sin(2x) = 1

sin(2x) = 1/2

When there is a variable n = π/6, sin(π/6) = 1/2 [refer to the unit circle].

2x = π/6

x = π/12

sin(2x) - 1 = 0

sin(2x) = 1

When there is a variable n = π/2, sin(π/2) = 1 [refer to the unit circle].

2x = π/2

x = π/4

Hope this helps!

$9.41

step-by-step explanation:

10 down (bang1)

5 up

5down (2)

2.5 up

2.5 down (3)

1.25 up

1.25 down (4)

now add them up : )

hoped i lol