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The variables x and y satisfy the differential equation dy/dx= xe^x+y. It is given that y = 0 when x = 0.
(i) Solve the differential equation, obtaining y in terms of x.
(ii) Explain why x can only take values that are less than 1.
Answers: 2
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The variables x and y satisfy the differential equation dy/dx= xe^x+y. It is given that y = 0 when x...
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