A ray of light passing from air through an equilateral glass prism undergoes minimum deviation, when the angle of incidence is 3/4th of the angle of prism. If the speed of light
in air is 3x10^8m/s, calculate the speed of light in the prism?

45° and speed of light in prism 2×10⁸m/s

Step-by-step explanation:

The minimum deviation of the equilateral glass prism will form 60° angle.

So angle of incidence = 3/4×60

= 3 ×15

= 45°

Minimum deviation = δmin

= 30

After finding the value of μ using prism law

μ = 1.41

Speed of light will be 2×10⁸m/s

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