13.6 the position of a point during the internal of time from t=0 to t=6 is given by s=2 t + 6t² tutm. a) what is the maximum velocity during this interval of time, and at what time does it occur? 6) what is the acceleration when the webrity is a maximum?

x = -3

y = -18

step-by-step explanation:

to solve by substitution, substitute one variable and solve for the other. then substitute again to find the remaining variable.

x-1/3(3x-9) = -3 since y=3x-9 substittute y.

x-1/3(3x-9)=-3

x + x +3 = -3

2x+3=-3

2x+3-3= -3-3

2x=-6

x=-3

substitute again into y=3x-9

y=3(-3)-9

y=-9-9

y=-18

you just switch the numbers basically so it would be 3/17

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