In how many years will the population of a town be 26901 from 24400 at the growth rate of 5% per annum ?​

2 years

Step-by-step explanation:

5% of 24,400 is 1,220

The 1st year the population of the town will be 25,620

( 24,400 + 1,220= 25,620)

The 2nd year the population of the town  will be 26,840

(25,620 + 1,220= 26,840)

By the time the 3rd year comes along the population of the town will already be over 26,901, so therefore the amount of years it would take for a population of 24,400 to 26,901 is 2 years.

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.