How can we write an algebraic expression to describe a two-digit number whose unit's digit is 5 less than the ten's digit?

Let x= the ones digit

Then x+5=the tens digit

Hence the equation is: 10(x+5)+x=x+5+x+63

10(x+5)+x=x+5+x+63

10x+50+x=2x+68

11x+50=2x+68

-2x-50  -2x-50

       9x=18  Divide both sides of the equation by 9

         x=2

Hence the number is 10(2+5)+2=10(7)+2=70+2=72.

160

step-by-step explanation:

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