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Mathematics, 14.07.2021 21:10 MGA20078

h(t)= ⎩ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎨ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎧ ​ 3 t ​ +6 t(t+4) t 2 +t+1 ​ , , , ​ t∈(−∞,−3) t∈[−3,3) t∈[3,∞) ​ h(0)=h(0)=h, left parenthesis, 0, right parenthesis, equals

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h(t)= ⎩ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎨ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎧ ​ 3 t ​ +6 t(t+4) t 2 +t+1 ​ , , , ​ t∈(−∞,−3) t∈[−3,3)...
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