What is the domain of the function y= sqrt x

- infinity < x< infinity
0 0 1 x

Step-by-step explanation:

I don't see really the actual answer options (you made a bad copy here).

so, I can only tell you what it is in my own terms and you need to associate to the actual answer option.

based on real numbers (not complex or imaginary) we cannot use the square root function on negative numbers.

the domain defined what values can be used for x.

so,

0<= x < +infinity

the answer is b: 18

step-by-step explanation:

use the pythagorean theorem to .

a^2+b^2=c^2

plug 18 for "r"

the 2 legs are 18 and 24

18^2+24^2=c^2

324+576=c^2

900=c^2

c=30

30-12=18

18 is the radius

: )

a, b, c, d are correct.

step-by-step explanation:

we have g(x) = 3 and are required to find which option is a translation of g(x).

now, 'translation' is a transformation which means to shift the function in any direction and the general form of translation is g(x) + k, where k is any real number.

so, according to the options we see that all are correct as they satisfy the general form of translation.

also, it can be seen from the graph below that the function g(x) = 3 is shifted from its position in all the four options.